The number of structural and configurational isomers of a bromo compound, $${C_5}{H_9}Br,$$ formed by the addition of $$HBr$$ to 2 - pentyne respectively are
A.
1 and 2
B.
2 and 4
C.
4 and 2
D.
2 and 1
Answer :
2 and 4
Solution :
Addition of $$HBr$$ of 2 - pentyne gives two structural
isomers (I) and (II)
\[C{{H}_{3}}-C\equiv C-C{{H}_{2}}C{{H}_{3}}\xrightarrow{HBr}\] \[\underset{\left( \text{I} \right)}{\mathop{C{{H}_{3}}C\left( Br \right)=CHC{{H}_{2}}C{{H}_{3}}}}\,\,\,+\] \[\underset{\left( \text{II} \right)}{\mathop{C{{H}_{3}}CH=C\left( Br \right)C{{H}_{2}}C{{H}_{3}}}}\,\]
Each one of these will exist as a pair of geometrical isomers. Thus, there are two structural and four configurational isomers.
Releted MCQ Question on Organic Chemistry >> Alkyl and Aryl Halide
Releted Question 1
Chlorobenzene can be prepared by reacting aniline with :
A.
hydrochloric acid
B.
cuprous chloride
C.
chlorine in presence of anhydrous aluminium chloride
D.
nitrous acid followed by heating with cuprous chloride
The number of structural and configurational isomers of a bromo compound, $${C_5}{H_9}Br,$$ formed by the addition of $$HBr$$ to 2 - pentyne respectively are