The number of real solutions of $$x - \frac{1}{{{x^2} - 4}} = 2 - \frac{1}{{{x^2} - 4}}$$ is
A.
0
B.
1
C.
2
D.
infinite
Answer :
0
Solution :
$${x^2} - 4 \ne 0$$
$$ \Rightarrow \,\,x \ne 2.$$ But the given equation implies that if $$x \ne 2$$ then $$x = 2.$$ This is a contradiction, so $$x$$ has no value
Releted MCQ Question on Algebra >> Quadratic Equation
Releted Question 1
If $$\ell ,m,n$$ are real, $$\ell \ne m,$$ then the roots by the equation: $$\left( {\ell - m} \right){x^2} - 5\left( {\ell + m} \right)x - 2\left( {\ell - m} \right) = 0$$ are