Question
The number of oxygen atoms present in $$1\,mole$$ of oxalic acid dihydrate is
A.
$$6 \times {10^{23}}$$
B.
$$6.023 \times {10^{34}}$$
C.
$$7.22 \times {10^{23}}$$
D.
$$36.13 \times {10^{23}}$$
Answer :
$$36.13 \times {10^{23}}$$
Solution :
One molecule of oxalic acid dihydrate $${\left( {COOH} \right)_2} \cdot 2{H_2}O$$ contains 6 oxygen atoms.
Number of oxygen atoms in $$1\,mole$$
$$\eqalign{
& = 6 \times 6.023 \times {10^{23}} \cr
& = 36.13 \times {10^{23}}\,{\text{atoms}} \cr} $$