Question
The number and type of bonds between two carbon atoms in $$Ca{C_2}$$ are:
A.
one sigma $$\left( \sigma \right)$$ and one pi $$\left( \pi \right)$$ bonds
B.
one sigma $$\left( \sigma \right)$$ and two pi $$\left( \pi \right)$$ bonds
C.
one sigma $$\left( \sigma \right)$$ and one and a half pi $$\left( \pi \right)$$ bonds
D.
one sigma $$\left( \sigma \right)$$ bond.
Answer :
one sigma $$\left( \sigma \right)$$ and two pi $$\left( \pi \right)$$ bonds
Solution :
Calcium carbide is an ionic compound $$\left( {C{a^{2 + }}{C^{2 - }}} \right)$$ which produces acetylene on reacting with water. Thus the structure of $${C^{2 - }}$$ is $${\left[ {C \equiv C} \right]^{2 - }}.$$ It has one $$\sigma $$ and two $$\pi $$ bonds. [ $$\because $$ A triple bond consists of one $$\sigma $$ and two $$\pi $$-bonds]