The major product obtained when $$B{r_2}/Fe$$ is treated with is
A.
B.
C.
D.
Answer :
Solution :
Electrophilic substitution takes place at electron rich positions. The ring attached with $$- NH$$ will have rich electron density due to resonance. As $$ortho$$ - position is blocked, the electrophile attacks the $$para$$ - position.