Question
The major product formed in the following reaction is
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
H
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{2}}Br\xrightarrow[C{{H}_{3}}OH]{C{{H}_{3}}{{O}^{-}}}\]
A.
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
H\,
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{2}}OC{{H}_{3}}\]
B.
\[C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\, \\
\,\,\,OC{{H}_{3}}
\end{smallmatrix}}{\mathop{-CH-}}\,C{{H}_{2}}C{{H}_{3}}\]
C.
\[C{{H}_{3}}-\overset{\begin{smallmatrix}
\,C{{H}_{3}} \\
|\,\,\,\,\,
\end{smallmatrix}}{\mathop{C=}}\,C{{H}_{2}}\]
D.
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
\,\,\,\,\,\,OC{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\]
Answer :
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
\,\,\,\,\,\,OC{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\]
Solution :