The hybrid state of carbon in ethyne, graphite and diamond are respectively
A.
$$s{p^2},sp,s{p^3}$$
B.
$$sp,s{p^2},s{p^3}$$
C.
$$s{p^3},s{p^2},sp$$
D.
$$s{p^2},s{p^3},sp$$
Answer :
$$sp,s{p^2},s{p^3}$$
Solution :
In ethyne, $$H - C \equiv C - H;C$$ is $$sp$$ hybridised.
In graphite, one $$C$$ atom is attached to 3 other $$C$$ atoms which is $$s{p^2}$$ hybridised.
In diamond, one $$C$$ atom is attached to 4 other $$C$$ atoms which is $$s{p^3}$$ hybridised.
Releted MCQ Question on Inorganic Chemistry >> Chemical Bonding and Molecular Structure
Releted Question 1
The compound which contains both ionic and covalent bonds is