Question

The graph of the curve $${x^2} = 3x - y - 2$$    is

A. between the lines $$x = 1$$  and $$x = \frac{3}{2}$$
B. between the lines $$x = 1$$  and $$x = 2$$
C. strictly below the line $$4y = 1$$  
D. None of these
Answer :   strictly below the line $$4y = 1$$
Solution :
$$y = - {x^2} + 3x - 2 = \frac{9}{4} - \left( {{x^2} - 3x + \frac{9}{4}} \right) - 2 = \frac{1}{4} - {\left( {x - \frac{3}{2}} \right)^2} \leqslant \frac{1}{4}.$$

Releted MCQ Question on
Algebra >> Quadratic Equation

Releted Question 1

If $$\ell ,m,n$$  are real, $$\ell \ne m,$$  then the roots by the equation: $$\left( {\ell - m} \right){x^2} - 5\left( {\ell + m} \right)x - 2\left( {\ell - m} \right) = 0$$         are

A. Real and equal
B. Complex
C. Real and unequal
D. None of these
Releted Question 2

The equation $$x + 2y + 2z = 1{\text{ and }}2x + 4y + 4z = 9{\text{ have}}$$

A. Only one solution
B. Only two solutions
C. Infinite number of solutions
D. None of these
Releted Question 3

Let $$a > 0, b > 0$$    and $$c > 0$$ . Then the roots of the equation $$a{x^2} + bx + c = 0$$

A. are real and negative
B. have negative real parts
C. both (A) and (B)
D. none of these
Releted Question 4

Both the roots of the equation $$\left( {x - b} \right)\left( {x - c} \right) + \left( {x - a} \right)\left( {x - c} \right) + \left( {x - a} \right)\left( {x - b} \right) = 0$$           are always

A. positive
B. real
C. negative
D. none of these.

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Quadratic Equation


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