Question
The formation of $$O_2^ + {\left[ {Pt{F_6}} \right]^ - }$$ is the basis for the formation of xenon fluorides. This is because
A.
$${O_2}$$ and $$Xe$$ have comparable sizes.
B.
both $${O_2}$$ and $$Xe$$ are gases.
C.
$${O_2}$$ and $$Xe$$ have comparable ionisation energies.
D.
Both (A) and (C).
Answer :
Both (A) and (C).
Solution :
(i) The first ionization energy of xenon ( 1, 170 $$kJ\,\,mo{l^ - }$$ ) is quite close to that of dioxygen $$\left( {1,180\,\,kJ\,\,mo{l^{ - 1}}} \right).$$
(ii) The molecular diameters of xenon and dioxygen are almost identical.
Based on the above similarities Barlett ( who prepared $$O_2^ + {\left[ {Pt{F_6}} \right]^ - }$$ compound ) suggested that since oxygen combines with $$Pt{F_6},$$ so xenon should also form similar compound with $$Pt{F_6}.$$