The escape velocity for a body projected vertically upwards from the surface of earth is $$11\,km/\,s.$$ If the body is projected at an angle of $${45^ \circ }$$ with the vertical, the escape velocity will be-
A.
$$11\sqrt 2 \,km/s$$
B.
$$22\,km/s$$
C.
$$11\,km/s$$
D.
$$\frac{{11}}{{\sqrt 2 }}\,km/s$$
Answer :
$$11\,km/s$$
Solution :
$${v_e} = \sqrt {2gR} $$
The escape velocity is independent of the angle at which the body is projected.
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