Question

The equation of the directrix of the parabola $${y^2} + 4y + 4x + 2 = 0$$     is-

A. $$x = - 1$$
B. $$x = 1$$
C. $$x = - \frac{3}{2}$$
D. $$x = \frac{3}{2}$$  
Answer :   $$x = \frac{3}{2}$$
Solution :
$$\eqalign{ & {y^2} + 4y + 4x + 2 = 0 \cr & {y^2} + 4y + 4 = - 4x + 2 \cr & {\left( {y + 2} \right)^2} = - 4\left( {x - \frac{1}{2}} \right) \cr} $$
It is of the form $${Y^2} = - 4AX$$
whose directrix is given by $$X=A$$
$$\therefore $$ Required equation is $$x - \frac{1}{2} = 1\,\,\, \Rightarrow x = \frac{3}{2}$$

Releted MCQ Question on
Geometry >> Parabola

Releted Question 1

Consider a circle with its centre lying on the focus of the parabola $${y^2} = 2px$$   such that it touches the directrix of the parabola. Then a point of intersection of the circle and parabola is-

A. $$\left( {\frac{p}{2},\,p} \right){\text{ or }}\left( {\frac{p}{2},\, - p} \right)$$
B. $$\left( {\frac{p}{2},\, - \frac{p}{2}} \right)$$
C. $$\left( { - \frac{p}{2},\,p} \right)$$
D. $$\left( { - \frac{p}{2},\, - \frac{p}{2}} \right)$$
Releted Question 2

The curve described parametrically by $$x = {t^2} + t + 1,\,\,y = {t^2} - t + 1$$      represents-

A. a pair of straight lines
B. an ellipse
C. a parabola
D. a hyperbola
Releted Question 3

If $$x+y=k$$   is normal to $${y^2} = 12x,$$   then $$k$$ is-

A. $$3$$
B. $$9$$
C. $$ - 9$$
D. $$ - 3$$
Releted Question 4

If the line $$x-1=0$$   is the directrix of the parabola $${y^2} - kx + 8 = 0,$$    then one of the values of $$k$$ is-

A. $$\frac{1}{8}$$
B. $$8$$
C. $$4$$
D. $$\frac{1}{4}$$

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Parabola


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