Question
The enolic form of ethyl acetoacetate as below has
The enolic form of ethyl acetoacetate as below has
A.
18 sigma bonds and 2 $$pi$$ - bonds
B.
16 sigma bonds and 1 $$pi$$ -bond
C.
9 sigma bonds and 2 $$pi$$ -bonds
D.
9 sigma bonds and 1 $$pi$$ -bond
Answer :
18 sigma bonds and 2 $$pi$$ - bonds
Solution :
The enolic form of ethyl acetoacetate has 16 single bonds i.e. $$16\sigma - $$ bonds and 2 double bonds i.e. $$2\sigma - $$ bonds and $$2\pi - $$ bonds.
Hence, the given structure has $$18\,\sigma - $$ bonds and $$2\pi - $$ bonds.
The enolic form of ethyl acetoacetate has 16 single bonds i.e. $$16\sigma - $$ bonds and 2 double bonds i.e. $$2\sigma - $$ bonds and $$2\pi - $$ bonds.
Hence, the given structure has $$18\,\sigma - $$ bonds and $$2\pi - $$ bonds.