the end product z in the given sequence of reactions is

The end product $$(Z)$$ in the given sequence of reactions is \[C{{H}_{3}}CH=CHCHO\xrightarrow{NaB{{H}_{4}}}\] \[X\xrightarrow[ZnC{{l}_{2}}]{HCl}Y\xrightarrow[\left( \text{ii} \right)\,{{H}^{+}}]{\left( \text{i} \right)\,KCN}Z\]

A. $$C{H_3}CH = CHC{H_2}COOH$$

B. $$C{H_3}C{H_2}C{H_2}COOH$$

C. $$C{H_3}CH = CHCOOH$$

D. $$C{H_3}CH\left( {Cl} \right)C{H_2}COOH$$

Answer : $$C{H_3}CH = CHC{H_2}COOH$$

Solution :
Carboxylic Acid mcq solution image

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

Releted Question 1

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

A. $$Cu$$

B. $$CuO$$

C. $$C{u_2}O$$

D. $$Cu + C{u_2}O + CuO$$

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Releted Question 2

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

A. the attack of $$^ - OH$$ at the carbonyl group,

B. the transfer of hydride to the carbonyl group,

C. the abstraction of proton from the carboxylic acid,

D. the deprotonation of $$PhC{H_2}OH.$$

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Releted Question 3

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$ is liberated. The $$'C'$$ of $$C{O_2}$$ comes from

A. methyl group

B. carboxylic acid group

C. methylene group

D. bicarbonate

View Answer

Releted Question 4

Benzoyl chloride is prepared from benzoic acid by

A. $$C{l_2},hv$$

B. $$S{O_2}C{l_2}$$

C. $$SOC{l_2}$$

D. $$C{l_2},{H_2}O$$

View Answer

The end product $$(Z)$$ in the given sequence of reactions is \[C{{H}_{3}}CH=CHCHO\xrightarrow{NaB{{H}_{4}}}\] \[X\xrightarrow[ZnC{{l}_{2}}]{HCl}Y\xrightarrow[\left( \text{ii} \right)\,{{H}^{+}}]{\left( \text{i} \right)\,KCN}Z\]

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$ is liberated. The $$'C'$$ of $$C{O_2}$$ comes from

Benzoyl chloride is prepared from benzoic acid by

Practice More Releted MCQ Question on
Carboxylic Acid

Practice More MCQ Question on Chemistry Section

The end product $$(Z)$$ in the given sequence of reactions is \[C{{H}_{3}}CH=CHCHO\xrightarrow{NaB{{H}_{4}}}\] \[X\xrightarrow[ZnC{{l}_{2}}]{HCl}Y\xrightarrow[\left( \text{ii} \right)\,{{H}^{+}}]{\left( \text{i} \right)\,KCN}Z\]

Releted MCQ Question on Organic Chemistry >> Carboxylic Acid

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

In the Cannizzaro reaction given below, \[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\] the slowest step is

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$ is liberated. The $$'C'$$ of $$C{O_2}$$ comes from

Benzoyl chloride is prepared from benzoic acid by

Practice More Releted MCQ Question on Carboxylic Acid

Practice More MCQ Question on Chemistry Section

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

Practice More Releted MCQ Question on
Carboxylic Acid