Question
The enantiomer of $$\alpha - D\left( + \right) - $$ glucose is
A.
$$\beta - D - \left( + \right) - {\text{glucose}}$$
B.
$$\alpha - D - \left( - \right) - {\text{glucose}}$$
C.
$$\alpha - L - \left( - \right) - {\text{glucose}}$$
D.
$$\beta - L - \left( - \right) - {\text{glucose}}$$
Answer :
$$\alpha - L - \left( - \right) - {\text{glucose}}$$
Solution :
In the $$D$$ family the more dextrorotatory anomer is named $$\alpha - D - .$$ In the $$L$$ family the more laevorotatory anomer is named $$\alpha \,L.$$