The electronic configuration of four atoms are given in brackets :
$$\eqalign{
& P\left( {1{s^2}2{s^2}2{p^1}} \right);Q\left( {1{s^2}2{s^2}2{p^5}} \right) \cr
& R\left( {1{s^2}2{s^2}2{p^6}3{s^1}} \right);S\left( {1{s^2}2{s^2}2{p^2}} \right) \cr} $$
The element that would most readily form a diatomic molecule is
A.
$$P$$
B.
$$Q$$
C.
$$R$$
D.
$$S$$
Answer :
$$Q$$
Solution :
By sharing of 1 electron each, both the atoms of $$Q$$ will get a complement octet.
Releted MCQ Question on Inorganic Chemistry >> Chemical Bonding and Molecular Structure
Releted Question 1
The compound which contains both ionic and covalent bonds is