The electronic configuration of an element is $$1{s^2},2{s^2}\,2{p^6},3{s^2}\,3{p^3}.$$ What is the atomic
number of the element, which is present just below the above element in the periodic table?
A.
33
B.
34
C.
36
D.
49
Answer :
33
Solution :
The element which present just below the given element will have outermost electronic configuration as $$4{s^2}4{p^3},$$ so its full electronic configuration is $$1{s^2},2{s^2}\,2{p^6},3{s^2}\,3{p^6},4{s^2},$$ $$3{d^{10}},4{p^3}$$ and hence, its atomic number is 33.
Releted MCQ Question on Inorganic Chemistry >> Classification of Elements and Periodicity in Properties
Releted Question 1
The correct order of second ionisation potential of carbon, nitrogen, oxygen and fluorine is