The degree of freedom of a molecule of a triatomic gas is
A.
2
B.
4
C.
6
D.
8
Answer :
6
Solution :
No. of degree of freedom $$= 3 K - N$$
where $$K$$ is no. of atom and $$N$$ is the number of relations between atoms. For triatomic gas,
$$K = 3,N{ = ^3}{C_2} = 3$$
No. of degree of freedom $$ = 3\left( 3 \right) - 3 = 6$$
Releted MCQ Question on Heat and Thermodynamics >> Kinetic Theory of Gases
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