Question

The correct product of the following sequence of reactions
\[{{\left( C{{H}_{3}} \right)}_{2}}CHCOOH\xrightarrow[\left( \text{ii} \right)\,{{H}_{2}}O]{\left( \text{i} \right)\,LiAl{{H}_{4}}}\]       \[\xrightarrow{PB{{r}_{3}}}\,\,\xrightarrow[DMSO]{KCN}\,\,\xrightarrow[\Delta ]{{{H}_{2}}{{O}^{+}},\,{{H}^{+}}}\]

A. \[{{\left( C{{H}_{3}} \right)}_{2}}CHCH\,Br.COOH\]
B. \[{{\left( C{{H}_{3}} \right)}_{2}}CHC{{H}_{2}}COOH\]  
C. \[{{\left( C{{H}_{3}} \right)}_{2}}CHC{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]
D. \[{{\left( C{{H}_{3}} \right)}_{2}}C=CHCOOH\]
Answer :   \[{{\left( C{{H}_{3}} \right)}_{2}}CHC{{H}_{2}}COOH\]
Solution :
\[-COOH\xrightarrow[{{H}_{2}}O]{LiAl{{H}_{4}}}-C{{H}_{2}}OH\]       \[\xrightarrow{PB{{r}_{3}}}-C{{H}_{2}}Br\xrightarrow[DMSO]{KCN}\]      \[-C{{H}_{2}}CN\xrightarrow[{{H}_{2}}O]{{{H}^{+}}}-C{{H}_{2}}COOH\]

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

Releted Question 1

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

A. $$Cu$$
B. $$CuO$$
C. $$C{u_2}O$$
D. $$Cu + C{u_2}O + CuO$$
Releted Question 2

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

A. the attack of $$^ - OH$$  at the carbonyl group,
B. the transfer of hydride to the carbonyl group,
C. the abstraction of proton from the carboxylic acid,
D. the deprotonation of $$PhC{H_2}OH.$$
Releted Question 3

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$  is liberated. The $$'C'$$ of $$C{O_2}$$  comes from

A. methyl group
B. carboxylic acid group
C. methylene group
D. bicarbonate
Releted Question 4

Benzoyl chloride is prepared from benzoic acid by

A. $$C{l_2},hv$$
B. $$S{O_2}C{l_2}$$
C. $$SOC{l_2}$$
D. $$C{l_2},{H_2}O$$

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