Question
The correct order regarding the electronegativity of hybrid orbitals of carbon is
A.
$$sp > s{p^2} < s{p^3}$$
B.
$$sp > s{p^2} > s{p^3}$$
C.
$$sp < s{p^2} > s{p^3}$$
D.
$$sp < s{p^2} < s{p^3}$$
Answer :
$$sp > s{p^2} > s{p^3}$$
Solution :
The correct order regarding the electronegativity of hybrid orbitals of carbon is $$sp > s{p^2} > s{p^3}$$ because in $$sp,s{p^2}$$ and $$s{p^3}$$ hybrid orbitals, $$s$$ - orbital character is 50%, 33.3% and 25% respectively. Due to higher $$s$$ - character electron attracting tendency, i.e.
electronegativity increases.