Question

The correct order of acidity for the following compounds is
Carboxylic Acid mcq question image

A. I > II > III > IV  
B. III > I > II > IV
C. III > IV > II > I
D. I > III > IV > II
Answer :   I > II > III > IV
Solution :
Due to $$ortho$$  - effect, (I) and (II) are stronger acids than (III) and (IV). Due to two $$ortho$$  hydroxyl groups in (I), it is stronger acid than (II). (III) is a stronger acid than (IV) because at $$m$$ - position, $$-OH$$  group cannot exert $$+R$$  effect but can only exert $$-I$$  effect while at $$p$$ - position, $$-OH$$  group exerts its strong $$+R$$  effect. Thus, the correct order of acidity is : I > II > III > IV.

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

Releted Question 1

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

A. $$Cu$$
B. $$CuO$$
C. $$C{u_2}O$$
D. $$Cu + C{u_2}O + CuO$$
Releted Question 2

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

A. the attack of $$^ - OH$$  at the carbonyl group,
B. the transfer of hydride to the carbonyl group,
C. the abstraction of proton from the carboxylic acid,
D. the deprotonation of $$PhC{H_2}OH.$$
Releted Question 3

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$  is liberated. The $$'C'$$ of $$C{O_2}$$  comes from

A. methyl group
B. carboxylic acid group
C. methylene group
D. bicarbonate
Releted Question 4

Benzoyl chloride is prepared from benzoic acid by

A. $$C{l_2},hv$$
B. $$S{O_2}C{l_2}$$
C. $$SOC{l_2}$$
D. $$C{l_2},{H_2}O$$

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