Question

The best method to purify impure acetone is

A. \[C{{H}_{3}}COC{{H}_{3}}+HCl\to \]     \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,\,\,OH \\ | \end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\xrightarrow{\text{heat}}\]     \[C{{H}_{3}}COC{{H}_{3}}\]
B. \[C{{H}_{3}}COC{{H}_{3}}+NaHS{{O}_{3}}\to \]      \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ \,\,\,C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,\,\,OH \\ | \end{smallmatrix}}{\mathop{-C-}}}\,S{{O}_{3}}Na\xrightarrow{N{{a}_{2}}C{{O}_{3}}}\]      \[C{{H}_{3}}COC{{H}_{3}}\]  
C. \[C{{H}_{3}}COC{{H}_{3}}+HCN\to \]     \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ \,CN \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,\,\,OH \\ | \end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\xrightarrow{HOH}\]     \[C{{H}_{3}}COC{{H}_{3}}\]
D. \[C{{H}_{3}}COC{{H}_{3}}+{{H}_{2}}S{{O}_{4}}\to \]     \[\underset{\begin{smallmatrix} | \\ \,\,\,\,\,\,\,\,\,OS{{O}_{3}}H \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,\,\,OH \\ | \end{smallmatrix}}{\mathop{C{{H}_{3}}-C-C{{H}_{3}}}}}\,\xrightarrow{\text{heat}}C{{H}_{3}}COC{{H}_{3}}\]
Answer :   \[C{{H}_{3}}COC{{H}_{3}}+NaHS{{O}_{3}}\to \]      \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ \,\,\,C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,\,\,OH \\ | \end{smallmatrix}}{\mathop{-C-}}}\,S{{O}_{3}}Na\xrightarrow{N{{a}_{2}}C{{O}_{3}}}\]      \[C{{H}_{3}}COC{{H}_{3}}\]

Releted MCQ Question on
Organic Chemistry >> Aldehyde and Ketone

Releted Question 1

The reagent with which both acetaldehyde and acetone react easily is

A. Fehling’s reagent
B. Grignard reagent
C. Schiff’s reagent
D. Tollen’s reagent
Releted Question 2

The Cannizzaro reaction is not given by

A. trimethylacetaldehye
B. acetaldehyde
C. benzaldehyde
D. formaldehyde
Releted Question 3

The compound that will not give iodoform on treatment with alkali and iodine is :

A. acetone
B. ethanol
C. diethyl ketone
D. isopropyl alcohol
Releted Question 4

Polarisation of electrons in acrolein may be written as

A. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - \mathop {CH}\limits^{{\delta ^ + }} = O$$
B. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - CH = \mathop O\limits^{{\delta ^ + }} $$
C. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = \mathop {CH}\limits^{{\delta ^ + }} - CH = O$$
D. $$\mathop {C{H_2}}\limits^{{\delta ^ + }} = CH - CH = \mathop O\limits^{{\delta ^ - }} $$

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Aldehyde and Ketone


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