The area of the region bounded by the curves $$y = \left| {x - 2} \right|,\,x = 1,\,x = 3$$ and the x-axis is-
A.
$$4$$
B.
$$2$$
C.
$$3$$
D.
$$1$$
Answer :
$$1$$
Solution :
The required area is shown by shaded region
$$\eqalign{
& A = \int\limits_1^3 {\left| {x - 2} \right|dx} \,\,\, = 2\int\limits_2^3 {\left( {x - 2} \right)dx} \cr
& = 2\left[ {\frac{{{x^2}}}{2} - 2x} \right]_2^3\,\,\, = 1 \cr} $$
Releted MCQ Question on Calculus >> Application of Integration
Releted Question 1
The area bounded by the curves $$y = f\left( x \right),$$ the $$x$$-axis and the ordinates $$x = 1$$ and $$x = b$$ is $$\left( {b - 1} \right)\sin \left( {3b + 4} \right).$$ Then $$f\left( x \right)$$ is-