Question

The amplitude of a particle executing $$SHM$$  is $$4\,cm.$$  At the mean position the speed of the particle is $$16\,cm/\sec.$$   The distance of the particle from the mean position at which the speed of the particle becomes $$8\sqrt 3 \,cm/s,$$   will be

A. $$2\sqrt 3 \,cm$$
B. $$\sqrt 3 \,cm$$
C. $$1\,cm$$
D. $$2\,cm$$  
Answer :   $$2\,cm$$
Solution :
At mean position velocity is maximum
$$\eqalign{ & {\text{i}}{\text{.e}}{\text{.,}}\,\,{v_{\max }} = \omega a \Rightarrow \omega = \frac{{{v_{\max }}}}{a} = \frac{{16}}{4} = 4 \cr & \therefore v = \omega \sqrt {{a^2} - {y^2}} \Rightarrow 8\sqrt 3 = 4\sqrt {{4^2} - {y^2}} \cr & \Rightarrow 192 = 16\left( {16 - {y^2}} \right) \Rightarrow 12 = 16 - {y^2} \cr & \Rightarrow y = 2\,cm. \cr} $$

Releted MCQ Question on
Oscillation and Mechanical Waves >> Simple Harmonic Motion (SHM)

Releted Question 1

Two bodies $$M$$ and $$N$$ of equal masses are suspended from two separate massless springs of spring constants $${k_1}$$ and $${k_2}$$ respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of $$M$$ to that of $$N$$ is

A. $$\frac{{{k_1}}}{{{k_2}}}$$
B. $$\sqrt {\frac{{{k_1}}}{{{k_2}}}} $$
C. $$\frac{{{k_2}}}{{{k_1}}}$$
D. $$\sqrt {\frac{{{k_2}}}{{{k_1}}}} $$
Releted Question 2

A particle free to move along the $$x$$-axis has potential energy given by $$U\left( x \right) = k\left[ {1 - \exp \left( { - {x^2}} \right)} \right]$$      for $$ - \infty \leqslant x \leqslant + \infty ,$$    where $$k$$ is a positive constant of appropriate dimensions. Then

A. at points away from the origin, the particle is in unstable equilibrium
B. for any finite nonzero value of $$x,$$ there is a force directed away from the origin
C. if its total mechanical energy is $$\frac{k}{2},$$  it has its minimum kinetic energy at the origin.
D. for small displacements from $$x = 0,$$  the motion is simple harmonic
Releted Question 3

The period of oscillation of a simple pendulum of length $$L$$ suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination $$\alpha ,$$ is given by

A. $$2\pi \sqrt {\frac{L}{{g\cos \alpha }}} $$
B. $$2\pi \sqrt {\frac{L}{{g\sin \alpha }}} $$
C. $$2\pi \sqrt {\frac{L}{g}} $$
D. $$2\pi \sqrt {\frac{L}{{g\tan \alpha }}} $$
Releted Question 4

A particle executes simple harmonic motion between $$x = - A$$  and $$x = + A.$$  The time taken for it to go from 0 to $$\frac{A}{2}$$ is $${T_1}$$ and to go from $$\frac{A}{2}$$ to $$A$$ is $${T_2.}$$ Then

A. $${T_1} < {T_2}$$
B. $${T_1} > {T_2}$$
C. $${T_1} = {T_2}$$
D. $${T_1} = 2{T_2}$$

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Simple Harmonic Motion (SHM)


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