Question
Surface tension of a liquid is $$70\,dyne/cm.$$ Its value in SI is
A.
$$70\,N/m$$
B.
$$7 \times {10^{ - 2}}\,N/m$$
C.
$$70 \times {10^2}\,N/m$$
D.
$$7 \times {10^3}\,N/m$$
Answer :
$$7 \times {10^{ - 2}}\,N/m$$
Solution :
$$\eqalign{
& 1\,dyne = {10^{ - 5}}N\,\& \,1\,cm = {10^{ - 2}}m \cr
& S = 70\frac{{dyne}}{{cm}} \cr
& = \frac{{70 \times {{10}^{ - 5}}\,N}}{{{{10}^{ - 2}}m}} \cr
& = 70 \times {10^{ - 3}}\,N/m. \cr
& \Rightarrow S = 7 \times {10^{ - 2}}N/m \cr} $$