Suppose the drift velocity $${v_d}$$ in a material varied with the applied electric field $$E$$ as $${v_d} \propto \sqrt E .$$ Then $$V-I$$ graph for a wire made of such a material is best given by :
A.
B.
C.
D.
Answer :
Solution :
$$\eqalign{
& i = neA{V_d}\,{\text{and}}\,{V_d} \propto \sqrt E \,\left( {{\text{Given}}} \right) \cr
& {\text{or,}}\,i \propto \sqrt E \cr
& {i^2} \propto E \cr
& {i^2} \propto V \cr} $$
Hence graph (C) correctly depicts the $$V-I$$ graph for a wire made of such type of material.
Releted MCQ Question on Electrostatics and Magnetism >> Electric Current
Releted Question 1
The temperature coefficient of resistance of a wire is 0.00125 per $$^ \circ C$$ At $$300\,K,$$ its resistance is $$1\,ohm.$$ This resistance of the wire will be $$2\,ohm$$ at.
The electrostatic field due to a point charge depends on the distance $$r$$ as $$\frac{1}{{{r^2}}}.$$ Indicate which of the following quantities shows same dependence on $$r.$$
A.
Intensity of light from a point source.
B.
Electrostatic potential due to a point charge.
C.
Electrostatic potential at a distance r from the centre of a charged metallic sphere. Given $$r$$ < radius of the sphere.