Stopping distance of a moving vehicle is directly proportional to
A.
square of the initial velocity
B.
square of the initial acceleration
C.
the initial velocity
D.
the initial acceleration
Answer :
square of the initial velocity
Solution :
Let $$s$$ be the distance travelled by the vehicle before it stops.
Final velocity $$\upsilon = 0,$$ initial velocity = $$u$$
Using equation of motion $${v^2} - {u^2} = 2aS$$
$${0^2} - {u^2} = 2aS$$
Stopping distance, $$S = - \frac{{{u^2}}}{{2a}}$$
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