Six teachers and six students have to sit round a circular table such that there is a teacher between any two students. The number of ways in which they can sit is
A.
$$6! \times 6!$$
B.
$$5! \times 6!$$
C.
$$5! \times 5!$$
D.
None of these
Answer :
$$5! \times 6!$$
Solution :
Six students $${S_1},{S_2},.....,{S_6}$$ can be arranged round a circular table in $$5 !$$ ways. Among these 6 students there are six vactant places, shown by dots $$\left( \bullet \right)$$ in which six teachers can sit in $$6 !$$ ways.
Hence, number of arrangement $$= 5 ! \times 6 !$$
Releted MCQ Question on Algebra >> Permutation and Combination
Releted Question 1
$$^n{C_{r - 1}} = 36,{\,^n}{C_r} = 84$$ and $$^n{C_{r + 1}} = 126,$$ then $$r$$ is:
Ten different letters of an alphabet are given. Words with five letters are formed from these given letters. Then the number of words which have at least one letter repeated are
Eight chairs are numbered 1 to 8. Two women and three men wish to occupy one chair each. First the women choose the chairs from amongst the chairs marked 1 to 4 ; and then the men select the chairs from amongst the remaining. The number of possible arrangements is