Question
$$\left( {S{i_2}{O_5}} \right)_n^{2n - }$$ anion is obtained when :
A.
no oxygen of a $$SiO_4^{4 - }$$ tetrahedron is shared with another $$SiO_4^{4 - }$$ tetrahedron
B.
one oxygen of a $$SiO_4^{4 - }$$ tetrahedron is shared with another $$SiO_4^{4 - }$$ tetrahedron
C.
two oxygen of a $$SiO_4^{4 - }$$ tetrahedron are shared with another $$SiO_4^{4 - }$$ tetrahedron
D.
three oxygen of a $$SiO_4^{4 - }$$ tetrahedron are shared with another $$SiO_4^{4 - }$$ tetrahedron
Answer :
three oxygen of a $$SiO_4^{4 - }$$ tetrahedron are shared with another $$SiO_4^{4 - }$$ tetrahedron
Solution :
Total No. oxygen atoms per silicon atom
$$ = \frac{1}{2} + \frac{1}{2} + \frac{1}{2} + 1 = 2.5$$
∴ Formula $$S{i_2}O_5^{2 - }.$$
Total No. oxygen atoms per silicon atom
$$ = \frac{1}{2} + \frac{1}{2} + \frac{1}{2} + 1 = 2.5$$
∴ Formula $$S{i_2}O_5^{2 - }.$$