Regarding $${F^ - }$$ and $$C{l^ - }$$ which of the following statement $$(s)$$ is/are correct?
$$\left( {\text{i}} \right)C{l^ - }$$ can give up an electron more easily than $${F^ - }.$$
$$\left( {{\text{ii}}} \right)C{l^ - }$$ is a better reducing agent than $${F^ - }.$$
$$\left( {{\text{iii}}} \right)C{l^ - }$$ is smaller in size than $${F^ - }.$$
$$\left( {{\text{iv}}} \right){F^ - }$$ can be oxidised more readily than $$C{l^ - }.$$
A.
(i) and (ii)
B.
(i), (ii) and (iv)
C.
(iii) and (iv)
D.
Only (i)
Answer :
Only (i)
Solution :
The electronegativity of $${F^ - }$$ $$ion$$ is high, so it accept an electron and $$C{l^ - }$$ $$ion$$ can give an electron more easily. Also the size of $${F^ - }$$ is smaller than chloride ion $$\left( {C{l^ - }} \right).$$
Releted MCQ Question on Inorganic Chemistry >> P - Block Elements
Releted Question 1
The reddish brown coloured gas formed when nitric oxide is oxidised by air is