Question

Reaction by which benzaldehyde cannot be prepared ?

A. Aldehyde and Ketone mcq option image$$ + Cr{O_2}C{l_2}$$   and $$C{S_2}$$  followed by $${H_3}{O^ + }$$
B. Aldehyde and Ketone mcq option image$$ + {H_2}$$  in presence of $$Pd{\text{ - }}BaS{O_4}$$
C. Aldehyde and Ketone mcq option image$$ + CO + HCl$$    in presence of $$anhy.$$  $$AlC{l_3}$$
D. Aldehyde and Ketone mcq option image$$ + Zn/Hg$$   and $$conc.\,HCl$$  
Answer :   Aldehyde and Ketone mcq option image$$ + Zn/Hg$$   and $$conc.\,HCl$$
Solution :
Aldehyde and Ketone mcq solution image
This reaction is known as Etard reaction.
Aldehyde and Ketone mcq solution image
This reaction is called Rosenmund reaction.
Aldehyde and Ketone mcq solution image
The above reaction is known as Gattermann-Koch aldehyde synthesis.
Aldehyde and Ketone mcq solution image
Thus, from the reactants given in option (D) benzaldehyde is not obtained.

Releted MCQ Question on
Organic Chemistry >> Aldehyde and Ketone

Releted Question 1

The reagent with which both acetaldehyde and acetone react easily is

A. Fehling’s reagent
B. Grignard reagent
C. Schiff’s reagent
D. Tollen’s reagent
Releted Question 2

The Cannizzaro reaction is not given by

A. trimethylacetaldehye
B. acetaldehyde
C. benzaldehyde
D. formaldehyde
Releted Question 3

The compound that will not give iodoform on treatment with alkali and iodine is :

A. acetone
B. ethanol
C. diethyl ketone
D. isopropyl alcohol
Releted Question 4

Polarisation of electrons in acrolein may be written as

A. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - \mathop {CH}\limits^{{\delta ^ + }} = O$$
B. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - CH = \mathop O\limits^{{\delta ^ + }} $$
C. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = \mathop {CH}\limits^{{\delta ^ + }} - CH = O$$
D. $$\mathop {C{H_2}}\limits^{{\delta ^ + }} = CH - CH = \mathop O\limits^{{\delta ^ - }} $$

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Aldehyde and Ketone


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