Question

Rahul has to write a project, Probability that he will get a project copy is $$'p'$$, probability that he will get a blue pen is $$'q'$$ and probability that he will get a black pen is $$\frac{1}{2}$$. If he can complete the project either with blue or with black pen or with both and probability that he completed the project is $$\frac{1}{2}$$ then $$p\left( {1 + q} \right)$$   is :

A. $$\frac{1}{2}$$
B. $$1$$  
C. $$\frac{1}{4}$$
D. $$2$$
Answer :   $$1$$
Solution :
Lets define the events as
Probability of getting project copy $$\left( A \right) = p$$
Probability of getting blue pen $$\left( B \right) = q$$
Probability of getting black pen $$\left( C \right) = \frac{1}{2}$$
Then,
$$\eqalign{ & {\text{ }}p\left( {AB\overline C } \right) + p\left( {AC\overline B } \right) + p\left( {ABC} \right) = \frac{1}{2} \cr & p.q.\frac{1}{2} + p.\frac{1}{2}\left( {1 - q} \right) + p.q.\frac{1}{2} = \frac{1}{2} \cr & \therefore \,pq + p - pq + pq = 1 \cr & \therefore \,p\left( {1 + q} \right) = 1 \cr} $$

Releted MCQ Question on
Statistics and Probability >> Probability

Releted Question 1

Two fair dice are tossed. Let $$x$$ be the event that the first die shows an even number and $$y$$ be the event that the second die shows an odd number. The two events $$x$$ and $$y$$ are:

A. Mutually exclusive
B. Independent and mutually exclusive
C. Dependent
D. None of these
Releted Question 2

Two events $$A$$ and $$B$$ have probabilities 0.25 and 0.50 respectively. The probability that both $$A$$ and $$B$$ occur simultaneously is 0.14. Then the probability that neither $$A$$ nor $$B$$ occurs is

A. 0.39
B. 0.25
C. 0.11
D. none of these
Releted Question 3

The probability that an event $$A$$ happens in one trial of an experiment is 0.4. Three independent trials of the experiment are performed. The probability that the event $$A$$ happens at least once is

A. 0.936
B. 0.784
C. 0.904
D. none of these
Releted Question 4

If $$A$$ and $$B$$ are two events such that $$P(A) > 0,$$   and $$P\left( B \right) \ne 1,$$   then $$P\left( {\frac{{\overline A }}{{\overline B }}} \right)$$  is equal to
(Here $$\overline A$$ and $$\overline B$$ are complements of $$A$$ and $$B$$ respectively).

A. $$1 - P\left( {\frac{A}{B}} \right)$$
B. $$1 - P\left( {\frac{{\overline A }}{B}} \right)$$
C. $$\frac{{1 - P\left( {A \cup B} \right)}}{{P\left( {\overline B } \right)}}$$
D. $$\frac{{P\left( {\overline A } \right)}}{{P\left( {\overline B } \right)}}$$

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Probability


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