Question
$$r$$ and $$r’$$ denote the angles inside an equilateral prism, as usual, in degrees. Consider that during some time interval from $$t = 0$$ to $$t = t,r’$$ varies with time as $$r' = 10 + {t^2}.$$ During this time $$r$$ will vary as (assume that $$r$$ and $$r’$$ are in degree)
$$r$$ and $$r’$$ denote the angles inside an equilateral prism, as usual, in degrees. Consider that during some time interval from $$t = 0$$ to $$t = t,r’$$ varies with time as $$r' = 10 + {t^2}.$$ During this time $$r$$ will vary as (assume that $$r$$ and $$r’$$ are in degree)
A.
$$50 - {t^2}$$
B.
$$50 + {t^2}$$
C.
$$60 - {t^2}$$
D.
$$60 + {t^2}$$
Answer :
$$50 - {t^2}$$
Solution :
In a prism: $$r + r' = A$$
$$\eqalign{ & \Rightarrow r = A - r' \cr & \therefore r = {60^ \circ } - \left( {10 + {t^2}} \right) = 50 - {t^2} \cr} $$
In a prism: $$r + r' = A$$
$$\eqalign{ & \Rightarrow r = A - r' \cr & \therefore r = {60^ \circ } - \left( {10 + {t^2}} \right) = 50 - {t^2} \cr} $$
