51.
In Fresnel's biprism experiment the width of 10 fringes is $$2\,cm$$ which are formed at a distance of 2 meter from the slit. If the wavelength of light is $$5100\,\mathop {\text{A}}\limits^ \circ $$ then the distance between two coherent sources will be
When light reflects from denser surface phase change of $$\pi $$ occurs.
53.
In figure, Young’s double slit experiment $$Q$$ is the position of the first bright fringe on the right side of $$O.$$ $$P$$ is the 11th fringe on the other side, as measured from $$Q.$$ If $$\lambda = 6000\,\mathop {\text{A}}\limits^ \circ ,$$ then $${S_1}B$$ will be equal to
54.
In a double slit experiment slits $${S_1},{S_2}$$ is illuminated by a coherent light of wavelength $$\lambda .$$ The slits are separated by a distance $$d.$$ The experimental set up is modified by using plane mirrors as shown in figure. Find the fringe width of interference pattern on the screen.
A
$$\frac{{\left( {3{D_1} + 2{D_2}} \right)\lambda }}{d}$$
B
$$\frac{{\left( {2{D_1} + 3{D_2}} \right)\lambda }}{d}$$
C
$$\frac{{\left( {3{D_2} - 3{D_1}} \right)\lambda }}{d}$$
D
$$\frac{{\left( {3{D_1} - 2{D_2}} \right)\lambda }}{{2d}}$$
55.
A light wave of wavelength $${\lambda _0}$$, propagates from point $$A$$ to point $$B.$$ We introduce in its path a glass plate of refractive index $$n$$ and thickness $$l.$$ The introduction of the plate alters the phase of the plate at $$B$$ by an angle $$\phi .$$ If $$\lambda $$ is the wavelength of lights on emerging from the plate, then
A
$$\Delta \phi = 0$$
B
$$\Delta \phi = \frac{{2\pi l}}{{{\lambda _0}}}$$
56.
In $$YDSE$$ a light containing two wavelengths $$500\,nm$$ and $$700\,nm$$ are used. Find the minimum distance where maxima of two wavelengths coincide. Given $$\frac{D}{d} = {10^3},$$ where $$D$$ is the distance between the slits and the screen and $$d$$ is the distance between the slits.
At the place where maxima for both the wavelengths coincide, $$y$$ will be same for both the maxima, i.e.,
$$\eqalign{
& \frac{{{n_1}{\lambda _1}D}}{d} = \frac{{{n_2}{\lambda _2}D}}{d} \cr
& \Rightarrow \frac{{{n_1}}}{{{n_2}}} = \frac{{{\lambda _1}}}{{{\lambda _2}}} = \frac{{700}}{{500}} = \frac{7}{5} \cr} $$
Minimum integral value of $${{n_2}}$$ is 5.
∴ Minimum distance of maxima of the two wavelengths from central fringe $$ = \frac{{{n_2}{\lambda _2}D}}{d} = 5 \times 700 \times {10^{ - 9}} \times {10^3} = 3.5\,mm.$$
57.
A beam of unpolarised light of intensity $${{I_0}}$$ is passed through a polaroid $$A$$ and then through another polaroid $$B$$ which is oriented so that its principal plane makes an angle of 45° relative to that of $$A.$$ The intensity of the emergent light is
58.
In a Young’s double slit experiment, $$12$$ fringes are observed to be formed in a certain segment of the screen when light of wavelength $$600\,nm$$ is used. If the wavelength of light is changed to $$400\,nm,$$ number of fringes observed in the same segment of the screen is given by