21.
The electric field intensity at all points in space is given by $$\vec E = \sqrt 3 \hat i - \hat j\,{\text{volt/metre}}{\text{.}}$$ The nature of equipotential lines in $$xy$$ -plane is given by
Electric field is perpendicular to equipotential surfaces from high to low potential.
22.
A point charge of magnitude $$ + 1\mu C$$ is fixed at $$\left( {0,0,0} \right).$$ An isolated uncharged spherical conductor, is fixed with its center at $$\left( {4,0,0} \right).$$ The potential and the induced electric field at the centre of the sphere is :
A
$$1.8 \times {10^5}\,V$$ and $$ - 5.625 \times {10^6}\,V/m$$
B
$$0\,V$$ and $$0\,V/m$$
C
$$2.25 \times {10^5}V$$ and $$ - 5.625 \times {10^6}\,V/m$$
23.
A hollow metal sphere of radius $$10\,cm$$ is charged such that the potential on its surface is $$80\,V.$$ The potential at the centre of the sphere is
In case of spherical metal conductor hollow or solid for an internal point (i.e. $$r < R$$ ) potential everywhere inside is same. It is maximum at the surface of sphere and further going out of sphere its value decreases.
So, according to above graph
$$\eqalign{
& {V_{{\text{in}}}} = {V_{{\text{centre}}}} = {V_{{\text{surface}}}} \cr
& = \frac{1}{{4\pi {\varepsilon _0}}} \times \frac{q}{R} = 80\,V\,\,\left[ {\because {V_{{\text{surface}}}} = 80\,V} \right] \cr} $$
24.
Four electric charges $$ + q, + q, - q$$ and $$- q$$ are placed at the corners of a square of side $$2L$$ (see figure). The electric potential at point $$A,$$ mid-way between the two charges $$+q$$ and $$+q$$ is
A
$$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{2q}}{L}\left( {1 + \frac{1}{{\sqrt 5 }}} \right)$$
B
$$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{2q}}{L}\left( {1 - \frac{1}{{\sqrt 5 }}} \right)$$
C
zero
D
$$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{2q}}{L}\left( {1 + \sqrt 5 } \right)$$
Potential at any distance $$r$$ due to a point charge is given by,
$$V = \frac{{kq}}{r}\,\,\left[ {k = \frac{1}{{4\pi {\varepsilon _0}}}} \right]$$
Given, $$V = 2{V_{{\text{positive}}}} + 2{V_{{\text{negative}}}}$$
$$\eqalign{
& = \frac{1}{{4\pi {\varepsilon _0}}}\left[ {\frac{{2q}}{L} - \frac{{2q}}{{L\sqrt 5 }}} \right] \cr
& V = \frac{{2q}}{{4\pi {\varepsilon _0}L}}\left( {1 - \frac{1}{{\sqrt 5 }}} \right) \cr} $$
25.
Figure shows a system of three concentric metal shells $$A,B$$ and $$C$$ with radii $$a,2a$$ and $$3a$$ respectively. Shell $$B$$ is earthed and shell $$C$$ is given a charge $$Q.$$ Now if shell $$C$$ is connected to shell $$A,$$ then the final charge on the shell $$B,$$ is equal to
26.
Charges $$+ q$$ and $$- q$$ are placed at points $$A$$ and $$B$$ respectively which are a distance $$2L$$ apart, $$C$$ is the midpoint between $$A$$ and $$B.$$ The work done in moving a charge $$+Q$$ along the semicircle $$CRD$$ is
In case I, when charge $$+Q$$ is situated at $$C.$$
Electric potential energy of system,
$${U_1} = \frac{1}{{4\pi {\varepsilon _0}}}\frac{{\left( q \right)\left( { - q} \right)}}{{2L}} + \frac{1}{{4\pi {\varepsilon _0}}}\frac{{\left( { - q} \right)Q}}{L} + \frac{1}{{4\pi {\varepsilon _0}}}\frac{{qQ}}{L}$$
In case II, when charge $$+Q$$ is moved from $$C$$ to $$D.$$
Electric potential energy of system in that case,
$${U_2} = \frac{1}{{4\pi {\varepsilon _0}}} \cdot \frac{{\left( q \right)\left( { - q} \right)}}{{2L}} + \frac{1}{{4\pi {\varepsilon _0}}} \cdot \frac{{qQ}}{{3L}} + \frac{1}{{4\pi {\varepsilon _0}}}\frac{{\left( { - q} \right)\left( Q \right)}}{L}$$
As we know that work done in moving a charge is equal to change in potential energy between the points it has been moved.
Work done, $$\Delta U = {U_2} - {U_1}$$
$$\eqalign{
& = \left( { - \frac{1}{{4\pi {\varepsilon _0}}}\frac{{{q^2}}}{{2L}} + \frac{1}{{4\pi {\varepsilon _0}}} \cdot \frac{{qQ}}{{3L}} - \frac{1}{{4\pi {\varepsilon _0}}}\frac{{qQ}}{L}} \right) - \left( { - \frac{1}{{4\pi {\varepsilon _0}}}\frac{{{q^2}}}{{2L}} - \frac{1}{{4\pi {\varepsilon _0}}} \cdot \frac{{qQ}}{L} + \frac{1}{{4\pi {\varepsilon _0}}}\frac{{qQ}}{L}} \right) \cr
& = \frac{{qQ}}{{4\pi {\varepsilon _0}}} \cdot \left( {\frac{1}{{3L}} - \frac{1}{L}} \right) = \frac{{qQ}}{{4\pi {\varepsilon _0}}}\frac{{\left( {1 - 3} \right)}}{{3L}} \cr
& = \frac{{ - 2qQ}}{{12\pi {\varepsilon _0}L}} = - \frac{{qQ}}{{6\pi {\varepsilon _0}L}} \cr} $$
27.
A charge $$+q$$ fixed at each of the points $$x = {x_0},x = 3{x_0},x = 5{x_0},...$$ upto $$\infty $$ on $$X$$-axis and charge $$-q$$ is fixed on each of the points $$x = 2{x_0},x = 4{x_0},...$$ upto $$\infty .$$ Here $${x_0}$$ is a positive constant. Take the potential at a point due to a charge $$Q$$ at a distance $$r$$ form it to be $$\frac{Q}{{4\pi {\varepsilon _0}r}},$$ then the potential at the origin due to above system of charges will be:
A
zero
B
infinite
C
$$\frac{q}{{8\pi {\varepsilon _0}{x_0}{{\log }_e}2}}$$
D
$$\frac{{q{{\log }_e}2}}{{4\pi {\varepsilon _0}{x_0}}}$$
28.
Four charges $${q_1} = 2 \times {10^{ - 8}}C,{q_2} = - 2 \times {10^{ - 8}}C,{q^3} = - 3 \times {10^{ - 8}}C,$$ and $${q_4} = 6 \times {10^{ - 8}}C$$ are placed at four corners of a square of side $$\sqrt 2 \,m.$$ What is the potential at the centre of the square?
29.
$$A$$ and $$B$$ are two points in an electric field. If the work done in carrying $$4.0\,C$$ of electric charge from $$A$$ to $$B$$ is $$16.0\,J,$$ the potential difference between $$A$$ and $$B$$ is
30.
The electric potential at a point $$\left( {x,y} \right)$$ in the $$x-y$$ plane is given by $$V = - kxy.$$ The field intensity at a distance $$r$$ from the origin varies as