Question
$$P$$ is a point. Two tangents are drawn from it to the parabola $${y^2} = 4x$$ such that the slope of one tangent is three times the slope of the other. The locus of $$P$$ is :
A.
a straight line
B.
a circle
C.
a parabola
D.
an ellipse
Answer :
a parabola
Solution :
Let $$P = \left( {\alpha ,\,\beta } \right).$$ Any tangent to the parabola is $$y = mx + \frac{a}{m}.$$ It passes through $$\left( {\alpha ,\,\beta } \right).$$ So, $$\beta = m\alpha + \frac{1}{m}\left( {\because {\text{ here }}a = 1} \right);\,\,\therefore \,{m^2}\alpha - \beta m + 1 = 0$$
Its roots are $${m_1},\,3{m_1}.$$ So, $${m_1} + 3{m_1} = \frac{\beta }{\alpha },\,\,\,{m_1}.3{m_1} = \frac{1}{\alpha }$$
$$\therefore \,\,3.{\left( {\frac{\beta }{{4\alpha }}} \right)^2} = \frac{1}{\alpha }{\text{ or }}3{\beta ^2} = 16\alpha $$
Thus, the locus is $$3{y^2} = 16x,$$ which is a parabola.