Question
Oxidation state of $$Fe$$ in $$F{e_3}{O_4}$$ is
A.
$$\frac{3}{2}$$
B.
$$\frac{4}{5}$$
C.
$$\frac{5}{4}$$
D.
$$\frac{8}{3}$$
Answer :
$$\frac{8}{3}$$
Solution :
Oxidation state of $$Fe$$ in $$F{e_3}{O_4}$$ is calculated as
$$\eqalign{
& \mathop F\limits^x {e_3}\mathop {{O_4}}\limits^{ - 2} \cr
& 3x + \left( { - 2 \times 4} \right) = 0 \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3x = + 8 \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = + \frac{8}{3} \cr} $$