Question

One of the lines in the emission spectrum of $$L{i^{2 + }}$$  has the same wavelength as that of the Ist line of Lyman series in hydrogen spectrum. The electronic transition corresponding to this line is $$n = 6 \to 3 = x.$$    Find the value of $$x.$$

A. 8
B. 3  
C. 7
D. 5
Answer :   3
Solution :
For Ist line of Lyman series in hydrogen spectrum
$$\frac{1}{\lambda } = R\left( 1 \right)\left( {\frac{1}{{{1^2}}} - \frac{1}{{{2^2}}}} \right) = \frac{3}{4}R$$
For $$L{i^{2 + }}\left[ {\frac{1}{\lambda } = R \times 9\left( {\frac{1}{{{3^2}}} - \frac{1}{{{6^2}}}} \right) = \frac{{3R}}{4}} \right]$$
which is satisfied by $$n = 6 \to n = 3.$$

Releted MCQ Question on
Modern Physics >> Atoms And Nuclei

Releted Question 1

If elements with principal quantum number $$n > 4$$  were not allowed in nature, the number of possible elements would be

A. 60
B. 32
C. 4
D. 64
Releted Question 2

Consider the spectral line resulting from the transition $$n = 2 \to n = 1$$    in the atoms and ions given below. The shortest wavelength is produced by

A. Hydrogen atom
B. Deuterium atom
C. Singly ionized Helium
D. Doubly ionised Lithium
Releted Question 3

An energy of $$24.6\,eV$$  is required to remove one of the electrons from a neutral helium atom. The energy in $$\left( {eV} \right)$$  required to remove both the electrons from a neutral helium atom is

A. 38.2
B. 49.2
C. 51.8
D. 79.0
Releted Question 4

As per Bohr model, the minimum energy (in $$eV$$ ) required to remove an electron from the ground state of doubly ionized $$Li$$ atom $$\left( {Z = 3} \right)$$  is

A. 1.51
B. 13.6
C. 40.8
D. 122.4

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