Question

One gas bleaches the colour of flowers by reduction, while the other by oxidation

A. $$CO\,{\text{and}}\,C{l_2}$$
B. $$S{O_2}\,{\text{and}}\,C{l_2}$$  
C. $${H_2}S\,{\text{and}}\,B{r_2}$$
D. $$N{H_3}\,{\text{and}}\,S{O_2}$$
Answer :   $$S{O_2}\,{\text{and}}\,C{l_2}$$
Solution :
$$S{O_2}$$  bleaches by reduction, while chlorine bleaches colour of flowers by oxidation.

Releted MCQ Question on
Physical Chemistry >> Redox Reaction

Releted Question 1

Which of the following represents a redox reaction?

A. $$NaOH + HCl \to NaCl + {H_2}O$$
B. $$BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$$
C. $$CuS{O_4} + 2{H_2}O \to Cu{\left( {OH} \right)_2} + {H_2}S{O_4}$$
D. $$Zn + 2HCl \to ZnC{l_2} + {H_2}$$
Releted Question 2

Which reaction involves neither oxidation nor reduction?

A. $$CrO_4^{2 - } \to C{r_2}O_7^{2 - }$$
B. $$Cr \to CrC{l_3}$$
C. $$Na \to N{a^ + }$$
D. $$2{S_2}O_3^{2 - } \to {S_4}O_6^{2 - }$$
Releted Question 3

$$Zn$$  gives $${H_2}$$  gas with $${H_2}S{O_4}$$  and $$HCl$$  but not with $$HN{O_3}$$  because

A. Zn acts as an oxidising agent when it reacts with $$HN{O_3}$$
B. $$HN{O_3}$$  is weaker acid than $${H_2}S{O_4}$$  and $$HCl$$
C. In electrochemical series, $$Zn$$  is above hydrogen
D. $$NO_3^ - $$  is reduced in preference to hydronium $$ion$$
Releted Question 4

A compound of $$Xe$$  and $$F$$  is found to have $$53.5\% $$  of $$Xe.$$  What is oxidation number of $$Xe$$  in this compound ?

A. $$-4$$
B. $$0$$
C. $$+4$$
D. $$+6$$

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Redox Reaction


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