Question
One end of a massless rope, which passes over a massless and frictionless pulley $$P$$ is tied to a hook $$C$$ while the other end is free. Maximum tension that the rope can bear is $$360\,N.$$ With what value of maximum safe acceleration $$\left( {{\text{in}}\,m{s^{ - 2}}} \right)$$ can a man of $$60\,kg$$ climb on the rope?
One end of a massless rope, which passes over a massless and frictionless pulley $$P$$ is tied to a hook $$C$$ while the other end is free. Maximum tension that the rope can bear is $$360\,N.$$ With what value of maximum safe acceleration $$\left( {{\text{in}}\,m{s^{ - 2}}} \right)$$ can a man of $$60\,kg$$ climb on the rope?
A.
16
B.
6
C.
4
D.
8
Answer :
4
Solution :
$$\eqalign{ & mg - T = ma \cr & \therefore a = g - \frac{T}{m} = 10 - \frac{{360}}{{60}} = 4\,m/{s^2} \cr} $$
$$\eqalign{ & mg - T = ma \cr & \therefore a = g - \frac{T}{m} = 10 - \frac{{360}}{{60}} = 4\,m/{s^2} \cr} $$
