Question
Nitrobenzene on reaction with $$conc.\,HN{O_3}/{H_2}S{O_4}$$ at $${80^ \circ }{\text{ - }}{100^ \circ }C$$ forms which one of the following products?
A.
1, 2 - dinitrobenzene
B.
1, 3 - dinitrobenzene
C.
1, 4 - dinitrobenzene
D.
1, 2, 4 - trinitrobenzene
Answer :
1, 3 - dinitrobenzene
Solution :
$$N{O_2}$$ group being electron withdrawing that's why it reduces the electron density at $$ortho$$ and $$para$$ - positions. Hence, as compare to $$ortho$$ and $$para$$ the $$meta$$ - position is electron rich on which the electrophile ( nitronium ion ) can easily attacks during nitration.
$$N{O_2}$$ group being electron withdrawing that's why it reduces the electron density at $$ortho$$ and $$para$$ - positions. Hence, as compare to $$ortho$$ and $$para$$ the $$meta$$ - position is electron rich on which the electrophile ( nitronium ion ) can easily attacks during nitration.