Question
Match the column I with column II and mark the appropriate choice.
|
Column I (Atom) |
|
Column II (No. of unpaired electrons) |
| a. |
$$_{15}P$$ |
1. |
6 unpaired electrons |
| b. |
$$_{24}Cr$$ |
2. |
2 unpaired electrons |
| c. |
$$_{26}Fe$$ |
3. |
3 unpaired electrons |
| d. |
$$_{14}Si$$ |
4. |
4 unpaired electrons |
A.
a - 2, b - 1, c - 3, d - 4
B.
a - 1, b - 3, c - 2, d - 4
C.
a - 3, b - 1, c - 4, d - 2
D.
a - 4, b - 2, c - 1, d - 3
Answer :
a - 3, b - 1, c - 4, d - 2
Solution :
$$\eqalign{
& _{15}P:\left[ {Ne} \right]3{s^2}3{p^3} \cr
& _{24}Cr:\left[ {Ar} \right]3{d^5}4{s^1} \cr
& _{26}Fe:\left[ {Ar} \right]4{s^2}3{d^6} \cr
& _{14}Si:\left[ {Ne} \right]3{s^2}3{p^2} \cr} $$