Let $${x_1},{x_2},......\,{x_n}$$ be $$n$$ observations such that $$\sum {x_i^2 = 400\,\,{\text{and }}\sum {{x_i} = 80.} } $$ Then the possible value of $$n$$ among the following is
A.
15
B.
18
C.
9
D.
12
Answer :
18
Solution :
We know that for positive real numbers $${x_1},{x_2},......\,{x_n}$$ A.M. of $${k^{th}}$$ power of $$x{'_i}s \geqslant {k^{th}}$$ the power of A.M. of $$x{'_i}s$$
$$\eqalign{
& \Rightarrow \,\,\frac{{\sum {x_1^2} }}{n} \geqslant {\left( {\frac{{\sum {{x_1}} }}{n}} \right)^2} \cr
& \Rightarrow \,\,\frac{{400}}{n} \geqslant {\left( {\frac{{80}}{n}} \right)^2} \cr} $$
$$ \Rightarrow \,\,n \geqslant 16.$$ So only possible value for $$n$$ = 18
Releted MCQ Question on Statistics and Probability >> Statistics
Releted Question 1
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