Let $$x, y, z$$ be three positive prime numbers. The progression in which $$\sqrt x ,\sqrt y ,\sqrt z $$ can be three terms (not necessarily consecutive) is
A.
A.P.
B.
G.P.
C.
H.P.
D.
none of these
Answer :
none of these
Solution :
If in A.P., $$\sqrt y = \sqrt x + \left( {n - 1} \right)d$$ and $$\sqrt z = \sqrt x + \left( {m - 1} \right)d$$
$$\therefore \,\,\frac{{\sqrt y - \sqrt x }}{{\sqrt z - \sqrt x }} = \frac{{n - 1}}{{m - 1}},$$ a rational number. As $$x, y, z$$ are prime, $$\frac{{\sqrt y - \sqrt x }}{{\sqrt z - \sqrt x }}$$ is irrational.
∴ irrational = rational (absurd). So, $$\sqrt x ,\sqrt y ,\sqrt z $$ are not in A.P.
Similarly, they are not in G.P. or H.P.
Releted MCQ Question on Algebra >> Sequences and Series
Releted Question 1
If $$x, y$$ and $$z$$ are $${p^{{\text{th}}}},{q^{{\text{th}}}}\,{\text{and }}{r^{{\text{th}}}}$$ terms respectively of an A.P. and also of a G.P., then $${x^{y - z}}{y^{z - x}}{z^{x - y}}$$ is equal to:
If $$a, b, c$$ are in G.P., then the equations $$a{x^2} + 2bx + c = 0$$ and $$d{x^2} + 2ex + f = 0$$ have a common root if $$\frac{d}{a},\frac{e}{b},\frac{f}{c}$$ are in-