Question

Let $$S =$$  the set of all triangles, $$P =$$  the set of all isosceles triangles, $$Q =$$  the set of all equilateral triangles, $$R =$$  the set of all right-angled triangles.
What do the sets $$P \cap Q$$  and $$R - P$$  represents respectively ?

A. The set of isosceles triangles; the set of non-isosceles right angled triangles  
B. The set of isosceles triangles; the set of right angled triangles
C. The set of equilateral triangles; the set of right angled triangles
D. The set of isosceles triangles; the set of equilateral triangles
Answer :   The set of isosceles triangles; the set of non-isosceles right angled triangles
Solution :
As given :
$$S =$$  the set of all triangles
$$P =$$  the set of all isosceles triangles
$$Q =$$  the set of all equilateral triangles
$$R =$$  the set of all right angled triangles
$$\therefore \,\,P \cap Q$$   represents the set of isosceles triangles and $$R - P$$  represents the set of non-isosceles right angled triangles.

Releted MCQ Question on
Calculus >> Sets and Relations

Releted Question 1

If $$X$$ and $$Y$$ are two sets, then $$X \cap {\left( {X \cup Y} \right)^c}$$   equals.

A. $$X$$
B. $$Y$$
C. $$\phi $$
D. None of these
Releted Question 2

The expression $$\frac{{12}}{{3 + \sqrt 5 + 2\sqrt 2 }}$$    is equal to

A. $$1 - \sqrt 5 + \sqrt 2 + \sqrt {10} $$
B. $$1 + \sqrt 5 + \sqrt 2 - \sqrt {10} $$
C. $$1 + \sqrt 5 - \sqrt 2 + \sqrt {10} $$
D. $$1 - \sqrt 5 - \sqrt 2 + \sqrt {10} $$
Releted Question 3

If $${x_1},{x_2},.....,{x_n}$$    are any real numbers and $$n$$ is any positive integer, then

A. $$n\sum\limits_{i = 1}^n {{x_i}^2 < {{\left( {\sum\limits_{i = 1}^n {{x_i}} } \right)}^2}} $$
B. $$\sum\limits_{i = 1}^n {{x_i}^2 \geqslant {{\left( {\sum\limits_{i = 1}^n {{x_i}} } \right)}^2}} $$
C. $$\sum\limits_{i = 1}^n {{x_i}^2 \geqslant n{{\left( {\sum\limits_{i = 1}^n {{x_i}} } \right)}^2}} $$
D. none of these
Releted Question 4

Let $$S$$ = {1, 2, 3, 4}. The total number of unordered pairs of disjoint subsets of $$S$$ is equal to

A. 25
B. 34
C. 42
D. 41

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