let ps be the median of the triangle with vertices p 22 q 6

Let $$PS$$ be the median of the triangle with vertices $$P\left( {2,\,2} \right),\,Q\left( {6,\, - 1} \right)$$ and $$R\left( {7,\,3} \right).$$ The equation of the line passing through $$\left( {1,\, - 1} \right)$$ and parallel to $$PS$$ is-

A. $$2x-9y-7=0$$

B. $$2x-9y-11=0$$

C. $$2x+9y-11=0$$

D. $$2x+9y+7=0$$

Answer : $$2x+9y+7=0$$

Solution :
$$S$$ is the midpoint of $$Q$$ and $$R$$
Therefore, $$S \equiv \left( {\frac{{7 + 6}}{2},\,\frac{{3 - 1}}{2}} \right) = \left( {\frac{{13}}{2},\,1} \right)$$
Straight Lines mcq solution image

Now slope of $$PS = m = \frac{{2 - 1}}{{2 - \frac{{13}}{2}}} = - \frac{2}{9}$$
Now equation of the line passing through $$\left( {1,\, - 1} \right)$$ and parallel to $$PS$$ is
$$y + 1 = - \frac{2}{9}\left( {x - 1} \right)\,\,\,{\text{or}}\,\,\,2x + 9y + 7 = 0$$

Releted MCQ Question on
Geometry >> Straight Lines

Releted Question 1

The points $$\left( { - a, - b} \right),\left( {0,\,0} \right),\left( {a,\,b} \right)$$ and $$\left( {{a^2},\,ab} \right)$$ are :

A. Collinear

B. Vertices of a parallelogram

C. Vertices of a rectangle

D. None of these

View Answer

Releted Question 2

The point (4, 1) undergoes the following three transformations successively.
(i) Reflection about the line $$y =x.$$
(ii) Translation through a distance 2 units along the positive direction of $$x$$-axis.
(iii) Rotation through an angle $$\frac{p}{4}$$ about the origin in the counter clockwise direction.
Then the final position of the point is given by the coordinates.

A. $$\left( {\frac{1}{{\sqrt 2 }},\,\frac{7}{{\sqrt 2 }}} \right)$$

B. $$\left( { - \sqrt 2 ,\,7\sqrt 2 } \right)$$

C. $$\left( { - \frac{1}{{\sqrt 2 }},\,\frac{7}{{\sqrt 2 }}} \right)$$

D. $$\left( {\sqrt 2 ,\,7\sqrt 2 } \right)$$

View Answer

Releted Question 3

The straight lines $$x + y= 0, \,3x + y-4=0,\,x+ 3y-4=0$$ form a triangle which is-

A. isosceles

B. equilateral

C. right angled

D. none of these

View Answer

Releted Question 4

If $$P = \left( {1,\,0} \right),\,Q = \left( { - 1,\,0} \right)$$ and $$R = \left( {2,\,0} \right)$$ are three given points, then locus of the point $$S$$ satisfying the relation $$S{Q^2} + S{R^2} = 2S{P^2},$$ is-

A. a straight line parallel to $$x$$-axis

B. a circle passing through the origin

C. a circle with the centre at the origin

D. a straight line parallel to $$y$$-axis

View Answer

Let $$PS$$ be the median of the triangle with vertices $$P\left( {2,\,2} \right),\,Q\left( {6,\, - 1} \right)$$ and $$R\left( {7,\,3} \right).$$ The equation of the line passing through $$\left( {1,\, - 1} \right)$$ and parallel to $$PS$$ is-

Releted MCQ Question on
Geometry >> Straight Lines

The points $$\left( { - a, - b} \right),\left( {0,\,0} \right),\left( {a,\,b} \right)$$ and $$\left( {{a^2},\,ab} \right)$$ are :

The straight lines $$x + y= 0, \,3x + y-4=0,\,x+ 3y-4=0$$ form a triangle which is-

If $$P = \left( {1,\,0} \right),\,Q = \left( { - 1,\,0} \right)$$ and $$R = \left( {2,\,0} \right)$$ are three given points, then locus of the point $$S$$ satisfying the relation $$S{Q^2} + S{R^2} = 2S{P^2},$$ is-

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Straight Lines

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Let $$PS$$ be the median of the triangle with vertices $$P\left( {2,\,2} \right),\,Q\left( {6,\, - 1} \right)$$ and $$R\left( {7,\,3} \right).$$ The equation of the line passing through $$\left( {1,\, - 1} \right)$$ and parallel to $$PS$$ is-

Releted MCQ Question on Geometry >> Straight Lines

The points $$\left( { - a, - b} \right),\left( {0,\,0} \right),\left( {a,\,b} \right)$$ and $$\left( {{a^2},\,ab} \right)$$ are :

The straight lines $$x + y= 0, \,3x + y-4=0,\,x+ 3y-4=0$$ form a triangle which is-

If $$P = \left( {1,\,0} \right),\,Q = \left( { - 1,\,0} \right)$$ and $$R = \left( {2,\,0} \right)$$ are three given points, then locus of the point $$S$$ satisfying the relation $$S{Q^2} + S{R^2} = 2S{P^2},$$ is-

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Releted MCQ Question on
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Straight Lines