Question

Let $$f:R \to \left[ {0,\,\infty } \right)$$     be such that $$\mathop {\lim }\limits_{x \to 5} f\left( x \right)$$   exists and $$\mathop {\lim }\limits_{x \to 5} \frac{{{{\left( {f\left( x \right)} \right)}^2} - 9}}{{\sqrt {\left| {x - 5} \right|} }} = 0.$$     Then $$\mathop {\lim }\limits_{x \to 5} f\left( x \right)$$   equals:

A. $$0$$
B. $$1$$
C. $$2$$
D. $$3$$  
Answer :   $$3$$
Solution :
$$\eqalign{ & \mathop {\lim }\limits_{x \to 5} \frac{{{{\left( {f\left( x \right)} \right)}^2} - 9}}{{\sqrt {\left| {x - 5} \right|} }} = 0 \cr & \mathop {\lim }\limits_{x \to 5} \left[ {{{\left( {f\left( x \right)} \right)}^2} - 9} \right] = 0\,\,\,\,\, \Rightarrow \mathop {\lim }\limits_{x \to 5} f\left( x \right) = 3 \cr} $$

Releted MCQ Question on
Calculus >> Limits

Releted Question 1

lf $$f\left( x \right) = \sqrt {\frac{{x - \sin \,x}}{{x + {{\cos }^2}x}}} ,$$     then $$\mathop {\lim }\limits_{x\, \to \,\infty } f\left( x \right)$$    is-

A. $$0$$
B. $$\infty $$
C. $$1$$
D. none of these
Releted Question 2

If $$G\left( x \right) = - \sqrt {25 - {x^2}} $$     then $$\mathop {\lim }\limits_{x\, \to \,{\text{I}}} \frac{{G\left( x \right) - G\left( I \right)}}{{x - 1}}$$     has the value-

A. $$\frac{1}{{24}}$$
B. $$\frac{1}{{5}}$$
C. $$ - \sqrt {24} $$
D. none of these
Releted Question 3

$$\mathop {\lim }\limits_{n\, \to \,\infty } \left\{ {\frac{1}{{1 - {n^2}}} + \frac{2}{{1 - {n^2}}} + ..... + \frac{n}{{1 - {n^2}}}} \right\}$$        is equal to-

A. $$0$$
B. $$ - \frac{1}{2}$$
C. $$ \frac{1}{2}$$
D. none of these
Releted Question 4

If $$\eqalign{ & f\left( x \right) = \frac{{\sin \left[ x \right]}}{{\left[ x \right]}},\,\,\left[ x \right] \ne 0 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = 0,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ x \right] = 0 \cr} $$
Where \[\left[ x \right]\] denotes the greatest integer less than or equal to $$x.$$ then $$\mathop {\lim }\limits_{x\, \to \,0} f\left( x \right)$$   equals

A. $$1$$
B. $$0$$
C. $$ - 1$$
D. none of these

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Limits


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