Question

Let $$a > 0, b > 0$$    and $$c > 0$$ . Then the roots of the equation $$a{x^2} + bx + c = 0$$

A. are real and negative
B. have negative real parts
C. both (A) and (B)  
D. none of these
Answer :   both (A) and (B)
Solution :
As $$a, b, c > 0, a, b, c$$    should be real (note that order
relation is not defined in the set of complex numbers)
∴ Roots of equation are either real or complex conjugate.
Let $$\alpha {\text{,}}\beta $$  be the roots of $$a{x^2} + bx + c = 0,$$    then
$$\alpha + \beta = - \frac{b}{a} = - ve,\,\,\,\,\,\,\alpha \beta = \frac{c}{a} = + ve$$
⇒ Either both $$\alpha {\text{,}}\beta $$  are $$- ve$$  (if roots are real) or both $$\alpha {\text{,}}\beta $$  have $$- ve$$  real parts (if roots are complex conjugate)

Releted MCQ Question on
Algebra >> Quadratic Equation

Releted Question 1

If $$\ell ,m,n$$  are real, $$\ell \ne m,$$  then the roots by the equation: $$\left( {\ell - m} \right){x^2} - 5\left( {\ell + m} \right)x - 2\left( {\ell - m} \right) = 0$$         are

A. Real and equal
B. Complex
C. Real and unequal
D. None of these
Releted Question 2

The equation $$x + 2y + 2z = 1{\text{ and }}2x + 4y + 4z = 9{\text{ have}}$$

A. Only one solution
B. Only two solutions
C. Infinite number of solutions
D. None of these
Releted Question 3

Let $$a > 0, b > 0$$    and $$c > 0$$ . Then the roots of the equation $$a{x^2} + bx + c = 0$$

A. are real and negative
B. have negative real parts
C. both (A) and (B)
D. none of these
Releted Question 4

Both the roots of the equation $$\left( {x - b} \right)\left( {x - c} \right) + \left( {x - a} \right)\left( {x - c} \right) + \left( {x - a} \right)\left( {x - b} \right) = 0$$           are always

A. positive
B. real
C. negative
D. none of these.

Practice More Releted MCQ Question on
Quadratic Equation


Practice More MCQ Question on Maths Section