It was calculated that a shell when fired from a gun with a certain velocity and at an angle of elevation $$\frac{{5\pi }}{{36}}\,rad$$ should strike a given target. In actual practice, it was found that a hill just prevented the trajectory. At what angle (rad) of elevation should the gun be fired to hit the target
A.
$$\frac{{5\pi }}{{36}}$$
B.
$$\frac{{11\pi }}{{36}}$$
C.
$$\frac{{7\pi }}{{36}}$$
D.
$$\frac{{13\pi }}{{36}}$$
Answer :
$$\frac{{13\pi }}{{36}}$$
Solution :
Ranges for complementary angles are same
∴ Required Required $$ = \frac{\pi }{2} - \frac{{5\pi }}{{36}} = \frac{{13\pi }}{{36}}$$
Releted MCQ Question on Basic Physics >> Kinematics
Releted Question 1
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