Question
Ionization energies of atoms $$A$$ and $$B$$ are $$400$$ and
$$300\,k\,cal\,mo{l^{ - 1}}$$ respectively. The electron
affinities of these atoms are $$80.0$$ and $$85.0\,k\,cal\,mo{l^{ - 1}}$$ respectively. Then which is the correct statement regarding electronegativity $$\chi ?$$
A.
$${\chi _A} < {\chi _B}$$
B.
$${\chi _A} > {\chi _B}$$
C.
$${\chi _A} = {\chi _B}$$
D.
$${\text{none of these}}$$
Answer :
$${\chi _A} > {\chi _B}$$
Solution :
Electronegativity of an atom $${\text{ = }}\frac{{IE + EA}}{{2 \times 62.5}}$$
where $$IE$$ and $$EA$$ are in $$k\,cal\,mo{l^{ - 1}}.$$