In the synthesis of sodium carbonate, the recovery of ammonia is done by treating $$N{H_4}Cl$$ with $$Ca{\left( {OH} \right)_2}.$$ The by-product obtained in this process is
A.
$$CaC{l_2}$$
B.
$$NaCl$$
C.
$$NaOH$$
D.
$$NaHC{O_3}$$
Answer :
$$CaC{l_2}$$
Solution :
Sodium carbonate is generally prepared by Solvay process. In this process, $$N{H_3}$$ is recovered when the solution containing $$N{H_4}Cl$$ is treated with $$Ca{\left( {OH} \right)_2}.$$ Calcium chloride is obtained as a by - product.
$$2N{H_4}Cl + Ca{\left( {OH} \right)_2} \to $$ $$2N{H_3} + CaC{l_2} + 2{H_2}O$$
Releted MCQ Question on Inorganic Chemistry >> S - Block Elements
Releted Question 1
A substance absorbs $$C{O_2}$$ and voilently reacts with water. The substance is